\n\n\n\nUsing the Power Rule Backwards<\/h2>\n\n\n\n This video is the foundational piece for using the power rule backwards to solve integrals. You can use the power rule like normal to check your answers. <\/p>\n\n\n\n\n
<\/path><\/path><\/svg><\/button><\/div><\/div>\n<\/div><\/figure>\n\n\n\nReview: Overview of Derivative and Anti-Derivative<\/h2>\n\n\n\n\n
<\/path><\/path><\/svg><\/button><\/div><\/div>\n<\/div><\/figure>\n\n\n\nIntegral of one Term<\/h2>\n\n\n\n\n
<\/path><\/path><\/svg><\/button><\/div><\/div>\n<\/div><\/figure>\n\n\n\nSolving eu<\/sup><\/h2>\n\n\n\n\n
<\/path><\/path><\/svg><\/button><\/div><\/div>\n<\/div><\/figure>\n\n\n\nTrig Function Integrals<\/h2>\n\n\n\n\n
<\/path><\/path><\/svg><\/button><\/div><\/div>\n<\/div><\/figure>\n\n\n\nReview: Finding Integrals with Anti-Derivative<\/h2>\n\n\n\n\n
<\/path><\/path><\/svg><\/button><\/div><\/div>\n<\/div><\/figure>\n\n\n\nPrevious Videos<\/h3>\n\n\n\nBig picture explanation<\/h2>\n\n\n\n This video is good at explaining these ideas conceptually.<\/p>\n\n\n\n\n
<\/path><\/path><\/svg><\/button><\/div><\/div>\n<\/div><\/figure>\n\n\n\nDerivatives of Natural Logs<\/h2>\n\n\n\n\n
<\/path><\/path><\/svg><\/button><\/div><\/div>\n<\/div><\/figure>\n\n\n\nDerivatives of Log Properties<\/h2>\n\n\n\n\n
<\/path><\/path><\/svg><\/button><\/div><\/div>\n<\/div><\/figure>\n\n\n\nDerivatives of ex<\/sup><\/h2>\n\n\n\n\n
<\/path><\/path><\/svg><\/button><\/div><\/div>\n<\/div><\/figure>\n\n\n\nDerivatives of ln, logs, and ex<\/sup><\/h2>\n\n
<\/path><\/path><\/svg><\/button><\/div><\/div>\n<\/div><\/figure>\n\n\n\nDerivatives of Units 5 & 6 in One Summary<\/h2>\n\n
<\/path><\/path><\/svg><\/button><\/div><\/div>\n<\/div><\/figure>\n\n\n\nProofs of ln and ex<\/sup> Derivatives<\/h2>\n\n
<\/path><\/path><\/svg><\/button><\/div><\/div>\n<\/div><\/figure>\n\n\n\nReview of Limits: <\/strong>If finding limits seems challenging, you can always review this video.<\/p>\n\n\n\n\n
<\/path><\/path><\/svg><\/button><\/div><\/div>\n<\/div><\/figure>\n\n\n\nHeart of Calculus: Applications of Derivatives & Integrals<\/h2>\n\n\n\n\n
<\/path><\/path><\/svg><\/button><\/div><\/div>\n<\/div><\/figure>\n\n\n\nMean Value Theorem (formal definition):<\/p>\n\n\n\n\n
<\/path><\/path><\/svg><\/button><\/div><\/div>\n<\/div><\/figure>\n\n\n\nContrasting Average Value and Average Rate of Change<\/p>\n\n\n\n\n
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<\/path><\/path><\/svg><\/button><\/div><\/div>\n<\/div><\/figure>\n\n\n\nWatch by Sunday: <\/h2>\n\n\n\n Mean Value Theorem (informal definition):<\/p>\n\n\n\n\n
<\/path><\/path><\/svg><\/button><\/div><\/div>\n<\/div><\/figure>\n\n\n\nImplicit Differentiation is the key to understanding Related Rates problems. Please review both these videos and write down questions with timestamps (like, 8:02) that we can review Sunday.<\/p>\n\n\n\n\n
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<\/path><\/path><\/svg><\/button><\/div><\/div>\n<\/div><\/figure>\n\n\n\nOptimization Practice<\/h2>\n\n\n\n If you can’t solve these questions, then please review the four videos below.<\/p>\n\n\n\n
An airplane is flying in a horizontal, straight-line path. The speed of the airplane is 100 meters per second, and its altitude is 1000 meters. What is the rate of change of the angle of elevation, , when the horizontal distance from a reference point P on the ground is 2,000 meter? <\/li> A ball is expanding at a rate of 0.25 inches per minute. How is the volume changing? <\/li> A cylinder is increasing its height at 2 centimeters per minute. How is its volume changing? <\/li><\/ul>\n\n\n\n\n
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